Calculus: Related Rates 2

Published by admin on February 18th, 2010

MORE AT http://www.mathtv.com/

This is part two of a discussion of related rates is a common topic in most calculus courses. Enjoy.

Duration : 0:6:50




25 Responses

  1. chihuasmex89 says:

    Beautiful!!!!!!!!! …
    Beautiful!!!!!!!!! you are a great teacher

  2. yankeeboy14534 says:

    THANK YOU SO MUCH! …
    THANK YOU SO MUCH! YOU JUST SAVED ME FROM FAILING MY CALC MID-TERM…..my teacher should take notes

  3. spacebird413 says:

    thank you
    thank you

  4. ednedfred says:

    Thank you, thank …
    Thank you, thank you, thank you.
    You made this very easy.
    Awesome.

  5. Grandmajoe123 says:

    Nice, slow …
    Nice, slow explanation. Thanks for the help! I love my math teacher, but he talks like 18 times faster than you and it’s impossible to learn.

  6. TIPorchestra93 says:

    oh my god thank you …
    oh my god thank you soo much. my calculus final is on tuesday and you made related rates so much easier to understand thank you

  7. himynameismollym says:

    you are genuinely a …
    you are genuinely a god for taking your time to do this. my ap calculus class is WAY above my head, but these videos help me sooooooo much. thanks so much!!!

  8. burnerj2000 says:

    u should of told us …
    u should of told us you plugged in 6 to the original equation so i could of followed easier but i found out. no problem

  9. BrendaGoes123 says:

    oh my god i …
    oh my god i understand!!!

  10. Wymorej says:

    wow thank you very …
    wow thank you very much your awesome

  11. MetalDraciel says:

    YOU ARE …
    YOU ARE AMAZING ! thats all i have to say .

    you made me understand this CLEARLY in less than 10 minutes while my ap cal teacher has been trying to do so for over a week now.

    Im gona send this to my fellow classmates. Thank you !

  12. barnamah says:

    thank you very much …
    thank you very much. The way you pust dy/dt on Y axis and dx/dt on X axis made it very easy and clear. My teacher was just introducing it I couldn’t understand. Thank you.

  13. BWpepperr says:

    Fantastic.
    Fantastic.

  14. jshhh890 says:

    this is the first …
    this is the first time i have ever understood any part of calculus.

  15. SylvanFP says:

    I think i’m in love …
    I think i’m in love with this channel :P thanks for the upload, it helps a ton!

  16. Aesalia says:

    wow i finally …
    wow i finally understand this lesson, im so happy lol

  17. TheBoredNerd says:

    holy crap… i …
    holy crap… i never understood the dy/dx, and why x isn’t solved like that… so THAT’S what they mean by “with respect to x”

    Thanks so much, just cleared up my conscious a bit!

  18. gart7777777 says:

    I’ve got a calculus …
    I’ve got a calculus exam in 4 days, My Professor is good but hard to understand. Thanks for clarifying

  19. SamJackShipper93 says:

    Incredible. You …
    Incredible. You taught me more with a couple of simple videos than my math teacher and tutor could in two weeks.

    Thank you so much! :)

  20. hiimboreddd says:

    you blow my mind …
    you blow my mind away. I took calculus 2x and now i FINALLY understand related rates. this 6 minute video was better than my previous professor teaching for 1 hour. simply amazing.

  21. hellokittydimaggio says:

    amazingg. i get it.
    amazingg. i get it.

  22. janitarjanitar says:

    let the man do his …
    let the man do his job, you can’t summarize his genious

  23. MJforLife18 says:

    So the steps are:

    So the steps are:
    1. Find the equation relating horizontal and vertical distances and the hypotenuse. (x,y, and 10, respectively)
    2. Find y based on this equation
    3. Derive that equation w/ respect to time
    4. Substitute y, x, and dx/dt into derivative equation, and solve for dy/dt.
    dy/dt represents the change in the vertical height of the ladder at a time t.

  24. bobobob141 says:

    t just means time …
    t just means time and so what it means i how much it changes at any instantaneous time say 2 seconds……..just means that you find the instantaneous rate of change for the value of 2 seconds………

  25. siddharthshah says:

    OMG thanks so much …
    OMG thanks so much !! This world needs more profs like u


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