Related Rates Problem Using Implicit Differentiation – For more free math videos, visit http://JustMathTutoring.com and click on the topic of your choice from the left hand side! I have organized links to over 100 FREE math videos made by me!
Happy studies!
Duration : 0:9:56
I have been …
I have been watching my teacher do these for 2 classes now…and you actually showed problem solving steps..I hate my professor. She just implies that we know EVERYTHING up to this point. She never recalls anything for us, and she just skips over steps. Thanks for the vids man
Ah this makes …
Ah this makes review so easy. I took calculus about 4 years ago XD.
techincally, you …
techincally, you will have to thank my wife – she told it to me!
thanks for the …
thanks for the DREDS mnemonic!
Would the rate of …
Would the rate of change be the same at 3 pm as at 4 pm ? thx for video !!!
You really strip …
You really strip down math to the problem solving adventure it should be. Everything is less intimidating when explained in real-world terms. Thanks!
kool I use that …
kool I use that book !
no. both distances …
no. both distances get longer with respect to time, so they should both be positive
shoudnt 35 be …
shoudnt 35 be negative?
DREDS, won’t be …
DREDS, won’t be forgetting that.. Good problem choice for a video.. took a lot of substitution and thinking to come to your answer
SIMPLER WAY!!!!
- …
SIMPLER WAY!!!!
-Draw and realize the right triangle.
-Add up the opposite distances (d=v*t)
-We already know the equation and the x, y, and z values b/c of pythagorean theorem (x=100, y=240, z= 260)
x^2 + y^2 = z^2
Now Differentiate:
2x(dx/dt) + 2y (dy/dt) = 2z(dz/dt)
Plug:
2(100)(0) + 2(240)(60) = 2(260)(dz/dt)
And Chug:
(0 + 28800)/ 520 = dz/dt
dz/dt = 55.38 km/h
ohhh wow. so much …
ohhh wow. so much work
Can you treat both …
Can you treat both the x and y movement as 1 variable?
Yes! I have the …
Yes! I have the same book!!!!
Yeah, you’re …
Yeah, you’re probably right.
Yes, I understand …
Yes, I understand that they were opposite directions, but I was merely commenting on how it might be confusing to a viewer that usually denotes x and y to perpendicular axes, and might instead use a and b rather than x and y to denote that sort of thing.
In this problem, …
In this problem, though, X and Y aren’t referring to the axes, though, there simply opposite directions.
I GOT THE SAME BOOK …
I GOT THE SAME BOOK! YAY! I LOVE U MAN
You know, you …
You know, you probably shouldn’t have said “the change in the x direction” because it doesn’t make sense on a set of axes. Technically dx/dt and dy/dt would both be on the y axis. It just sounds confusing when normally x and y are on perpendicular axes (like on a graph)
Awesome! Much …
Awesome! Much better than my teacher…
this problem is …
this problem is similar to the one i have in the Cal book..but thank you for helping me understand more about this type of problem…
Awesome, I use the …
Awesome, I use the book.
thank you so much, …
thank you so much, you are a lifesaver for my calc. test tom, i’m swinging by a donation
Thanks! Helped me a …
Thanks! Helped me a bunch, and you explained it very clearly.
Thank you for …
!!!
Thank you for posting this video it really helped me out